All x satisfying the inequality (cot –1 x ) 2 – 7(cot –1 x ) + 10 > 0, lie in the interval
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
All x satisfying the inequality
(cot–1x)2 – 7(cot–1x) + 10 > 0, lie in the interval
(cot–1x)2 – 7(cot–1x) + 10 > 0, lie in the interval
- (–
- (cot5, cot4)
- (–
- (cot2,
Answer
(C) (– ∞ , cot5) ∪ (cot2, ∞ )
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let W denotes the words in the English dictionary. Define the relation R by R = (x, y) ∈ W × W : the words x…
- The solution set of x^ 2 -3 x+4 x+1 >1, x R is
- Let A = x R : x is not a positive integer . Define a function f : A → R as f(x)= 2 x x-1 , then f is:
- Let f and g be increasing and decreasing functions respectively from [0, ) to [0, ) Let h(x)=f(g(x)) If…
- Let A = 2, 3, 4 and X = 0, 1, 2, 3, 4 , then which of the following statements is correct
- The range of the function y = l og 3 (5 + 4x – x 2 ) is
- A = 1, 2, 3, 4 , B = 1, 2, 3, 4, 5, 6 are two sets, and function f: A B is defined by f(x)=x+2 ∀ x ∈ A, then…
- cos –1 (cos(–5)) + sin –1 (sin(6)) – tan –1 (tan(12)) is equal to (The inverse trigonometric functions takes…
More Sets, Relations and Functions questions · Browse all practice questions