When a proton has velocity v =(2 i +3 j ) 10^ 6 ~m / s it experiences a force of F =-1.28…
Physics · JEE Advanced · NTA Exams — Magnetic Effects of Current and Magnetism
When a proton has velocity\(\overrightarrow{\mathrm{v}}=(2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}) \times 10^{6} \mathrm{~m} / \mathrm{s}\)it experiences a force of\(\overrightarrow{\mathrm{F}}=-1.28 \times 10^{-13} \hat{\mathrm{k}} \mathrm{~N}\).When its velocity is along +z axis, it experiences a force along +x axis. What is magnetic field?
- \(-0.4 \hat{\mathrm{j}} \mathrm{~T}\)
- \(0.4 \hat{\mathrm{j} T}\)
- \(-0.4 \hat{\mathrm{i}} \mathrm{~T}\)
- \(0.4 \hat{\mathrm{k}} \mathrm{~T}\)
Answer
(A) -0.4 j ~T
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