H _ 3 C - C CH [ 2. CH _ 3 CH _ 2 Br ] 1. NaNH _ 2 ~A [ Pd ^ 2 - BaSO _ 4 ] H _ 2 ~B :
Chemistry · JEE Advanced · NTA Exams — Hydrocarbons
\(\mathrm{H}_{3} \mathrm{C}-\mathrm{C} \equiv \mathrm{CH} \xrightarrow[\text { 2. } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Br}]{\text { 1. } \mathrm{NaNH}_{2}} \mathrm{~A}\) \(\xrightarrow[\mathrm{Pd}^{2}-\mathrm{BaSO}_{4}]{\mathrm{H}_{2}} \mathrm{~B}\) :
- A is \(\mathrm{H}_{3} \mathrm{C}-\mathrm{CH}_{2}-\mathrm{C} \equiv \mathrm{CH}\)
- A is \(\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{2} \mathrm{CH}_{3}\)
- B is
- B is
Answer
(B) A is CH _ 3 - C C - CH _ 2 CH _ 3, (C) B is
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