There are N cells in the circuit of figure. The emf and internal resistance of each cell…
Physics · Class 12 · CBSE — Current Electricity
There are N cells in the circuit of figure. The emf and internal resistance of each cell are \(\varepsilon\) and r respectively. The points A and B in the circuit divide the circuit into n and (N - n) cells. The current in the circuit is:

- \(\frac {\varepsilon}r\)
- \(\frac {n\varepsilon}r\)
- \(\frac {N\varepsilon}{nr}\)
- Zero
Answer
(D) Zero
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If a current of 1.5 ampere flows through a metallic wire for 3 hours, then how many electrons would flow…
- The specific resistance of a conductor increases with:
- A steady current of 8 mA flows through a wire. The number of electrons passing through a cross-section of the…
- In good conductors of electricity the type of bonding that exist is
- 3 identical bulbs are connected in series and these together dissipate a power P. If now the bulbs are…
- Which of the following is responsible for the flow of current in a conductor?
- The ratio of masses of three wires is 1 : 2 : 3 and that of their lengths is 3 : 2 : 1. If the wires are made…
- Which of the following shows correct range of conductivity? (i) Conductors : 10 4 to 10 7 ohm –1 m –1 (ii)…
More Current Electricity questions · Browse all practice questions