PhCH _ 2 CH _ 2 COOH Ag _ 2 O PhCH _ 2 CH _ 2 COOAg Br _ 2 PhCH _ 2 CH _ 2 Br + CO _ 2 +…
Chemistry · JEE Advanced · NTA Exams — Carboxylic Acids
\(\mathrm{PhCH}_{2} \mathrm{CH}_{2} \mathrm{COOH} \xrightarrow{\mathrm{Ag}_{2} \mathrm{O}} \mathrm{PhCH}_{2} \mathrm{CH}_{2} \mathrm{COOAg} \xrightarrow{\mathrm{Br}_{2}}\) \(\mathrm{PhCH}_{2} \mathrm{CH}_{2} \mathrm{Br}+\mathrm{CO}_{2}+\mathrm{AgBr} .\) The reaction is known as Hunsdiecker reaction. Choose incorrect statement(s) regarding the Hunsdiecker reaction.
- A more convenient way to perform the Hunsdiecker reaction is the use of a mixture of acid and mercuric oxide.
- Reaction involves radical intermediates.
- The trend in the yield of the resulting halide is primary > secondary > tertiary.
- The reaction starts with decarboxylation.
Answer
(C) The trend in the yield of the resulting halide is primary > secondary > tertiary., (D) The reaction starts with decarboxylation.
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