A spring of force constant k is cut into two pieces such that one piece is double the…
Physics · JEE Main · NTA Exams — Properties of Solids and Liquids
A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then, the long piece will have a force constant of
- \(\frac{2}{3} k\)
- \(\frac{3}{2} \mathrm{k}\)
- \(3 \mathrm{k}\)
- \(6 \mathrm{k}\)
Answer
(B) 3 2 k
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