The area bounded by the curve y=x(1- x) and positive x- axis between x=e^ -1 and x=e is
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
The area bounded by the curve \(y=x(1-\ln x)\) and positive \(x-\) axis between \(x=e^{-1}\) and \(x=e\) is
- \(\left(\frac{e^{2}-4 e^{-2}}{5}\right)\)
- \(\left(\frac{e^{2}-5 e^{-2}}{4}\right)\)
- \(\left(\frac{4 e^{2}-e^{-2}}{5}\right)\)
- \(\left(\frac{5 e^{2}-e^{-2}}{4}\right)\)
Answer
(B) ( e^ 2 -5 e^ -2 4 )
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