The area bounded by y = x 2 – 4 and x + y = 2 is
Mathematics · JEE Main · NTA Exams — Integral Calculus
The area bounded by y = x2 – 4 and x + y = 2 is
- \(\frac{75}{6}\)
- \(\frac{100}{6}\)
- \(\frac{125}{6}\)
- \(\frac{150}{6}\)
Answer
(C) 125 6
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