Equation of tangents to the ellipse x^ 2 9 + y^ 2 4 =1, which are perpendicular to the…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
Equation of tangents to the ellipse\(\frac{x^{2}}{9}+\frac{y^{2}}{4}=1,\)which are perpendicular to the line 3x + 4y = 7, are
- \(4 x-3 y= \pm 6 \sqrt{5}\)
- \(4 x-3 y= \pm \sqrt{12}\)
- \(4 x-3 y= \pm \sqrt{2}\)
- 4x – 3y = ± 1
Answer
(A) 4 x-3 y= 6 5
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The lines x + y = |a| and ax – y = 1 intersect each other in the first quadrant. Then, the set of all…
- A hyperbola passes through the point P( 2 , 3 ) and has foci at ( 2,0) . Then the tangent to this hyperbola…
- If one end of a focal chord AB of the parabola y^ 2 =8 x is at A ( 1 2 ,-2 ) , then the equation of the…
- For the two circles x 2 + y 2 = 16 and x 2 + y 2 - 2y = 0, there is/are:
- The equation of the latus rectum of the ellipse 9x 2 + 4y 2 –18x – 8y – 23 = 0 are
- The minimum distance of 4 x^ 2 +y^ 2 +4 x-4 y+5=0 from the line -4 x+3 y=3 is
- A circle touches x axis at +3 distance and cuts an intercept of 8 in +ve direction of y axis. Its equation is–
- The equation of the straight line which passes through the intersection of the lines x – y – 1 = 0 and 2x –…
More Co-ordinate Geometry questions · Browse all practice questions