A curve y = f ( x ) passes through (1, 1) and tangent at P ( x , y ) cuts the x -axis and…
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
A curve y = f(x) passes through (1, 1) and tangent at P(x, y)
cuts the x-axis and y axis at A and B respectively such that BP : AP = 3 : 1, then
cuts the x-axis and y axis at A and B respectively such that BP : AP = 3 : 1, then
- equation of curve is xy′ – 3y = 0
- normal at (1, 1) is x + 3y = 4
- curve passes through (2, 1/8)
- equation of curve is xy′ + 3y = 0
Answer
(A) equation of curve is xy ′ – 3 y = 0
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