The amplitude of a wave disturbance propagating along positive x-axis is given by y= 1…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
The amplitude of a wave disturbance propagating along positive x-axis is given by \(y=\frac{1}{1+x^{2}}\) at t = 0 and\(y=\frac{1}{1+(x-1)^{2}}\) at t = 2 s where x and y are in metres. The shape of the wave disturbance does not change with time. The velocity of the wave is
- 0.5 m/s
- 1 m/s
- 2 m/s
- 4 m/s
Answer
(A) 0.5 m/s
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