A particle having charge q and mass m starts moving from the origin under the action of…
Physics · Class 12 · CBSE — Moving Charges and Magnetism
A particle having charge q and mass m starts moving from the origin under the action of an electric field \(\vec{E}=E_{0} \hat{i}\) and \(\vec{B}=B_{0} \hat{i}\) with a velocity \(v=v_{0} \hat{j}\) . The speed of the particle will become \(\frac{\sqrt{5}}{2} v_{0}\) after a time
- \(\frac{m v_{0}}{2 q E}\)
- \(\frac{m v_{0}}{q E}\)
- \(\frac{\sqrt{3} m v_{0}}{2 q E}\)
- \(\frac{\sqrt{5} m v_{0}}{2 q E}\)
Answer
(A) m v_ 0 2 q E
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