Five digit numbers divisible by 3 are formed using 0, 1, 2, 3, 4, 6 and 7 without…
Mathematics · JEE Main · NTA Exams — Permutations and Combinations
Five digit numbers divisible by 3 are formed using 0, 1, 2, 3, 4, 6 and 7 without repetition. Total number of such numbers are
- 600
- 3125
- 120
- 216
Answer
(D) 216
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- There are four candidates for the post of a lecturer in Mathematics and one is to be selected by votes of 5…
- There are p-points in a plane, no three of which are in the same straight line with the exception of q…
- The number of parallelograms that can be formed from a set of four parallel lines intersecting another set of…
- In a touring cricket team, there are 16 players in all including 5 bowlers and 2 wicket-keepers. How many…
- The total number of times the digit 3 will be written when listing the integers from 1 to 1000 is
- There are 4 letter boxes in a post office. In how many ways can a man post 8 distinct letters ?
- If the number of five digit numbers with distinct digit and 2 at the 10 th place is 336k, then k is equal to :
- If n and r are two positive integers such that n ≥ r, then ^ n C_ r-1 + ^ n C_ r is equal to :
More Permutations and Combinations questions · Browse all practice questions