A body executes simple harmonic motion. The potential energy (PE), kinetic energy (KE)…
Physics · NEET · NTA Exams — Oscillations and Waves
A body executes simple harmonic motion. The potential energy (PE), kinetic energy (KE) and total energy (TE) are measured as a function of displacement y. Which of the following statement is true?
- TE is zero when x = 0
- PE is maximum when x = 0
- KE is maximum when x = 0
- KE is maximum when x is maximum
Answer
(C) KE is maximum when x = 0
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A mass suspended separately by two different springs of spring constant k 1 and k 2 gives the time period T 1…
- The number of possible natural oscillations of column in a pipe closed at one end of length 85 cm whose…
- Two periodic waves of intensities A_ 1 and 1_ 2 pass through a region at the same time in the same direction…
- Given below are two statements Statement I : Wave in a stretched string is transverse. Statement II : String…
- A body executes simple harmonic motion. The potential energy (P.E), kinetic energy (K.E.) and total energy…
- A transverse wave is described by the equation y=y_ n 2 (f t- x ) . The maximum particle velocity is equal to…
- The equation y=A 2 ( t T - x ) . where the symbols carry the usual meaning and A, T and λ are positive…
- The displacement y of a wave traveling in the x-direction is given by y=10^ -4 (600 t-2 x+ 3 ) metres, where…
More Oscillations and Waves questions · Browse all practice questions