_ h 0 (a+3 h)-3 (a+2 h)+3 (a+h)- a h^ 3 is
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
\(\lim _{h \rightarrow 0} \frac{\sin (a+3 h)-3 \sin (a+2 h)+3 \sin (a+h)-\sin a}{h^{3}}\) is
- sin a
- –sin a
- cos a
- –cos a
Answer
(D) –cos a
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