The ends of a stretched wire of length L are fixed at x = 0 and x = L . In one…
Physics · JEE Advanced · NTA Exams — Oscillations and Waves
The ends of a stretched wire of length L are fixed at x = 0
and x = L. In one experiment, the displacement of the wire is y1 = A sin(px/L) sinwt and energy is E1 and in another experiment its displacement is y2 = A sin(2px/L) sin 2wt and energy is E2. Then
and x = L. In one experiment, the displacement of the wire is y1 = A sin(px/L) sinwt and energy is E1 and in another experiment its displacement is y2 = A sin(2px/L) sin 2wt and energy is E2. Then
- E2 = E1
- E2 = 2E1
- E2 = 4E1
- E2 = 16E1.
Answer
(C) E 2 = 4 E 1
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