40% of a mixture of 0.2 mol of N 2 and 0.6 mol of H 2 reacts to give NH 3 according to…
Chemistry · JEE Main · NTA Exams — Equilibrium
40% of a mixture of 0.2 mol of N2 and 0.6 mol of H2 reacts to give NH3 according to the equation :
\(\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3}\)
at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases are
\(\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3}\)
at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases are
- 4 : 5
- 5 : 4
- 7 : 10
- 8 : 5
Answer
(A) 4 : 5
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