If the binding energy per nucleon in _ 1 ^ 7 Li and _ 2 ^ 4 He nuclei are 5.60 MeV and…
Physics · JEE Main · NTA Exams — Atoms and Nuclei
If the binding energy per nucleon in \({ }_{1}^{7} \mathrm{Li} \text { and }{ }_{2}^{4} \mathrm{He}\) nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction \({ }_{3}^{7} \mathrm{Li}+\rho \rightarrow 2{ }_{2}^{4} \mathrm{He}\) energy of proton must be
- 28.24 MeV
- 17.28 MeV
- 1.46 MeV
- 39.2 MeV
Answer
(B) 17.28 MeV
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