A hydrogen atom makes a transition from n = 5 to n = 1 orbit. The wavelength of photon…
Physics · Class 12 · CBSE — Atoms
A hydrogen atom makes a transition from n = 5 to n = 1 orbit. The wavelength of photon emitted is \(\lambda\) . The wavelength of photon emitted when it makes a transition from n = 5 to n = 2 orbit is
- \(\frac{8}{7} \lambda\)
- \(\frac{16}{7} \lambda\)
- \(\frac{24}{7} \lambda\)
- \(\frac{32}{7} \lambda\)
Answer
(D) 32 7
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