The compound in which * C uses its sp 3 hybrid orbitals for bond formation is : (1989)
Chemistry · JEE Advanced · NTA Exams — Chemical Bonding and Molecular Structure
The compound in which \(\stackrel{*}{\mathrm{C}}\) uses its sp3 hybrid orbitals for bond formation is : (1989)
- \(\mathrm{H} \stackrel{*}{\mathrm{C}} \mathrm{OOH}\)
- \(\left(\mathrm{H}_{2} \mathrm{~N}\right)_{2} \stackrel{*}{\mathrm{C}} \mathrm{O}\)
- \(\left(\mathrm{CH}_{3}\right)_{3} \stackrel{*}{\mathrm{C}} \mathrm{OH}\)
- \(\mathrm{CH}_{3} \stackrel{*}{\mathrm{C}} \mathrm{HO}\)
Answer
(C) ( CH _ 3 )_ 3 * C OH
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