The normal boiling point of a liquid ‘X’ is 400 K. Which of the following statement is…

Chemistry · JEE Advanced · NTA Exams — Chemical Thermodynamics

1. at 400 K and 1 atm pressure \(\Delta \mathrm{G}=0\)
2. at 400 K and 2 atm pressure \(\Delta \mathrm{G}=+\mathrm{ve}\)
3. at 400 K and 0.1 atm pressure \(\Delta G=-v e\)
4. at 410 K and 1 atm pressure \(\Delta \mathrm{G}=+\mathrm{ve}\)

Answer

(A) at 400 K and 1 atm pressure G =0, (B) at 400 K and 2 atm pressure G =+ ve, (C) at 400 K and 0.1 atm pressure G=-v e

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