The logarithm of the equilibrium constant, log K of the cell reaction of the cell Zn (5)…
Chemistry · NEET · NTA Exams — Electrochemistry
The logarithm of the equilibrium constant, log K of the cell reaction of the cell \(\mathrm{Zn}(5)\left|\mathrm{Zn}^{+2}(\mathrm{aq})\right|\left|\mathrm{Cu}^{2+}(\mathrm{aq})\right| \mathrm{Cu}(5) ; \Delta \mathrm{E}^{\mathrm{a}}=1.1 \mathrm{~V}\) is:
- \(\frac{1.1}{0.0291}\)
- \(\frac{-1.1}{0.0291}\)
- \(\frac{0.0291}{1.1}\)
- \(\frac{1.1}{0.0593}\)
Answer
(A) 1.1 0.0291
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