In the arrangement shown, if the surface is smooth, the acceleration of the block m 2…
Physics · JEE Advanced · NTA Exams — Laws of Motion
In the arrangement shown, if the surface is smooth, the acceleration of the block m2 will be:
- \(\frac{m_{2} g}{4 m_{1}+m_{2}}\)
- \(\frac{2 m_{2} g}{4 m_{1}+m_{2}}\)
- \(\frac{2 m_{2} g}{m_{1}+4 m_{2}}\)
- \(\frac{2 m_{1} g}{m_{1}+m_{2}}\)
Answer
(A) m_ 2 g 4 m_ 1 +m_ 2
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