Amines — practice questions
38 curated practice questions from Amines (Chemistry JEE Advanced, NTA Exams) — 35 hard, 3 medium. Every question includes the final answer free; step-by-step worked solutions with a free account.
- Assertion (A) : In order to convert R–Cl to pure R–NH 2 , Gabriel pthalimide synthesis can be used. Reason (R) : With…
- CH _ 3 CN Na + C _ 2 H _ 2 OH X The compound X is
- In the following reaction (2007) The structure of the major product X is
- (A) [ [ H ]] Reduction Primary amine The compound (A) may be :
- Aniline in a set of reactions yielded a product D The structure of the product (D) would be
- Which of the following amines will show positive Liebermann’s nitroso test :
- Hydrogen bonding plays a cental role in the following phenomena : (2014)
- (A) H _ 2 / Pt 1° Amine (B) H _ 2 / Pt 2° Amine (A) and (B) respectively are :
- Assertion : Aniline on reaction with NaNO 2 /HCl at 0°C followed by coupling with β-naphthol gives a dark blue coloured…
- What is the end product in the sequence of following reactions ? C _ 6 H _ 6 [333 ~K ] HNO _ 3 - H _ 2 SO _ 4 ~A Sn /…
- Which of the following reacts with hinsberg’s reagent (Benzene sulphonyl chloride) to form the product soluble in KOH ?
- A mixture of three amines (pri., sec. and tert.) can be prepared by :
- A mixture of three amines can be separated into individual one by :
- Which of the following on reduction with hydrogen and Raney nickel gives benzylamine ?
- Chlorobenzene can be prepared by reacting aniline with
- Acetamide is treated separately with the following reagents. Which one of these would give methylamine ?
- Ethyl amine undergoes oxidation in the presence of KMnO 4 to form
- Reaction of RCONH 2 with a mixture of Br 2 and KOH gives RNH 2 as the main product. The intermediates involved in the…
- Match the List I with List II and pick the correct matching from the codes given below : List - I List - II (Reactants)…
- Assertion (A) : Aniline hydrogen sulphate, on heating, forms a mixture of o-and p-amino benzene sulphonic acid. Reason…
- Correct option(s) for the following sequence of reactions is(are) (2021)
- When methyl iodide is treated with ammonia, the product obtained is/are :
- Examine the following two structures for the anilinium ion and choose the correct statement from the ones given below :
- The boiling points of amines and their corresponding alcohols and acids vary in the order :
- Assertion (A) : In Hoffmann Bromamide reaction, the amine formed has one carbon atom less than the parent 1° amide…
- Assertion (A) : In strongly acidic solutions, aniline becomes more reactive towards electrophilic reagents. Reason (R)…
- The correct functional group X and the reagent/reaction conditions Y in the following scheme are
- Ethyl amine on heating with CS 2 in presence of HgCl 2 forms
- The compound which on reaction with aqueous nitrous acid at low temperature produces an oily nitrosoamine, is
- Assertion (A) : In strongly acidic solutions, aniline becomes more reactive towards electrophilic reagents. Reason (R)…
- Assertion (A) : n-Propylamine has a higher boiling point than trimethylamine. Reason (R) : Among n-propylamine…
- Assertion (A) : Me 3 N reacts with BF 3 whereas Ph 3 N does not. Reason (R) : The electron pair on nitrogen atom in Ph…
- Primary, secondary and tertiary amines can be distinguished by the action of :
- Assertion (A) : Benzene diazonium chloride does not give tests for nitrogen. Reason (R) : N 2 gas is lost during…
- A mixture of 1°, 2° and 3° amines can be separated by Hinsberg’s reagent which is
- Which of the following amides will not undergo Hofmann bromamide reaction ?
- A solution of colourless salt H on boiling with excess NaOH produces a non-flammable gas. The gas evolution ceases…
- ( x ) C _ 4 H _ 11 ~N + HNO _ 2 C _ 4 H _ 10 O (3° alcohol) hence, (X) will give :